Question

Find the indicated intercept(s) of the graph of the function.

Answer 1

x-intercepts of \[f(x) =\frac{ x+7 }{ x ^{2}+5x-3 }\]

Answer 2

@julian25 or @jim_thompson5910 can you help?

Answer 3

plug in f(x) = 0, then solve for x

Answer 4

i dont get it .. but 0 for all x's?

Answer 5

No, f(x)=0
0=(x+7)/(x^2+5x-3)

Answer 6

A. (-7,0)
B.\[\frac{ 7 }{ 3 } , 0 \]
C. (7,0)
D. none

Answer 7

so (x+7)/5x^2 - 3??

Answer 8

nope, when you have any function in the form
\[\frac{ x+meh' }{blablablablablabla+x+bla-x^e }=0\] you just take the numerator, so
\[x+meh'=0\], or in your case
\[x+7=0\]

Answer 9

@Umangiasd can you show me exactally how to solve this cause im kind of lost

Answer 10

okay, the x intercepts indicate where the function "cuts" the x-axis, that means where y=0
so, as f(x)=y, we equalate f(x)=0, and we will have
\[f(x)=\frac{ x+7 }{ x^2+5x-3 } =0\]
Now, as i stated before that equation is just equal to
x+7=0, so our x=-7
And your point will be the one formed for x=-7 and y=0

Answer 11

okay makes sense thank you for explaining!