Find the vertical asymptotes, if any, of the graph of the rational function.

Question

erinweeks · Answer

$$f(x) = \frac{ x }{ x ^{2} +1}$$

erinweeks · Answer

@Umangiasd could you help me with a few more?

anonymous · Answer

Sure, do you know limits?

erinweeks · Answer

A. x = 1	

B. x = -1	

C. x = -1, x = 1	

D. no vertical asymptote

erinweeks · Answer

not really

anonymous · Answer

Okay, that will make it a little bit harder, the vertical asymptote exists when x indeterminate the function for a value of it
As an example
$$\frac{ 1 }{ x }$$, when x=0 doesn't have a solution, because you can't divide by 0, so, there is a vertical asymptote of that function
in yours
$$f(x)= \frac{ x }{ x^2 +1 }$$
so x^2 +1 = 0 for x=?

erinweeks · Answer

im guessing mine doesnt have one

anonymous · Answer

$$x^2+1=0 \leftarrow \rightarrow x^2=-1$$ so, your function is continous for all R, and in fact, it hasn't a vertical asymptote c:

erinweeks · Answer

okay so it would be -1

anonymous · Answer

no, no, no x^2=-1 doesn't exist for real numbers, so, x^2+1 is never 0, that means you don't have a vertical asymptote xD