How do you factor 3x^4-3? Can you please help me? I need to answer this. Thankyou.
can you first factor out 3 from 3x^4-3 ?
First always look for a common factor. Then look at number of terms: If 2 terms, try difference of squares or sum or difference of cubes.
hartnn, thankyou! I'll try that!
good! if you get stuck, we'll be here to help :)
Thankyou!! I always need help with my Math homework XD I'm not that good but I am willing to learn.
oh, and bdw, \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
Thankyou! That's very nice of you :">
Is the answer 3(x^2+1)(x^2-1) ?
you are on right path! but notice that you can further factor x^2-1 :)
So far, so good, but after you factor, you need to check each factor to see if you can factor some more.
So I have to factor it again? I'm kinda stuck XDD
same thing what you have done, \(a^2-b^2= (a+b)(a-b) \\ (x^2-1^2) =... ?\)
Look at each factor, and try this again: If 2 terms, try difference of squares or sum or difference of cubes.
Thankyou both! :)) I'll try that right now! Thanks. You're both great help!
For x^2-1 is it (x+1)(x-1) ?
correct :)
Thankyou. I still have to figure out x^2 + 1. I'm stuck again XDD. haha.
now are you aware of imaginary numbers ? [if not, keep x^2+1 as it is] or does this belong to imaginary/complex numbers ?
I'm not really aware of it... Sorry
x^2+1 does not have real factors, here, lets assume real factorization so, your final answer will be \(\large 3 (x+1)(x-1)(x^2+1)\) thats it!
Thankyou so much
you are most welcome ^_^
\[3x^4 - 3\] \[=3(x^4 - 1)\] \[=3(x^2 + 1)(x^2 -1)\] \[=3(x^2 + 1)(x + 1)(x - 1)\]
if and when you learn imaginary numbers, x^2+1 will be factorized as \((x+i)(x-i)\) till then , you can ignore this :)
Thankyou both! I'm moving on to the next problem. Thankyousomuch for helping me with this. :))
wlcm
x^6 + 26x^3 - 27 is it equal to : (x^3 + 27)(x^3 - 1) ?
Yes, but you're not done with factoring. Look at both binomials.
If 2 terms, try difference of squares or sum or difference of cubes.
@MoeshaKiel Did you finish this problem?
Yes. I did. Thanks to the both of you :)) you were awesome help!
ok, wlcm
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