Question

How do you factor x^6 - 36 + 24y - 4y^2 ? :))

Answer 1

When you have 4 terms, try factoring by parts.

Answer 2

How do you mean by parts?

Answer 3

Also called factoring by grouping.

Answer 4

Oh... Thankyou! :)) I'll try that.

Answer 5

Factor a common factor out of the first two terms, and factor out a common factor out of the last two terms.

Answer 6

LET X^6 remain in one side and factorise the other part i mean - 36 + 24y - 4y^2

Answer 7

Thanks :))

Answer 8

:)

Answer 9

@Curious9876 Good point.

Answer 10

Thnx @mathstudent55

Answer 11

Following @Curious9876 advice, look at it this way.
x^6 - 36 + 24y - 4y^2
x^6 - (36 - 24y + 4y^2)
Now rewrite the trinomial in descending order of the degree of y.

Answer 12

Is it -(6-2y)^2 ? (for -36+24y-4y^2 that is?)

Answer 13

No, but almost.
x^6 - (36 - 24y + 4y^2)
x^6 - (4y^2 - 24y + 36)
Factor the trinomial inside the parentheses.

Answer 14

Oh. Thankyou :)

Answer 15

x^6 - (2y-6)^2 ?

Answer 16

first find such two numbers whose sum is -24 and product=4.36=144

Answer 17

Great. Now you have a difference of squares.

Answer 18

Thankyou :) but what do I do with the x^6? Do I just leave it as it is?

Answer 19

x^6 = (x^3)^2

Answer 20

@MoeshaKiel tell me such two numbers whose sum is -24 and product=4.36=144

Answer 21

@Curious9876 I'll think about it...

Answer 22

x to the 6th is x cubed squared. that is why this is a difference of squares.

Answer 23

yep @mathstudent55

Answer 24

@mathstudent55 oh.. thanks :)
how do I write the final answer? I'm kinda stuck...

Answer 25

(x^3)^2 - (x - 2)^2 follows the pattern a^2 - b^2, which factors into (a + b)(a - b)