Question

differentiate ln sin sx

Answer 1

is this sx or 5x?

Answer 2

hi @Gimantha
\(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)

can you clarify your question ?
sin x or sin 5x ?

Answer 3

ln sin 2x differentiate it

Answer 4

do you know the chain rule ?

Answer 5

have you tried it atleast once ?

Answer 6

yeas fro chain rule

Answer 7

so, \([\ln (\sin 2x)]' = \dfrac{1}{\sin 2x} [\sin 2x]' \)
got this step ? can you continue ?

Answer 8

\[2(\cos2x)/(\sin2x)\]