Question

Multiply (4x – 3)^2.

A. 16x^2 + 9

B. 16x^2 – 24x + 9

C. 16x^2 – 12x + 9

D. 16x^2 – 9

Answer 1

Is D the correct answer?

Answer 2

How??
Can you explain why D??

Answer 3

\[(a-b)(a+b) = a^2 - b^2\]

This is not applicable here..

Answer 4

Use this here :
\[(a-b)^2 = a^2 + b^2 - 2ab\]

Answer 5

careful...

Answer 6

\[(4x)^{2} + (-3)^{2} - 2(4x-3)\]

Answer 7

is this correct?

Answer 8

No..

Answer 9

Last term is not right..

First two terms are looking nice to me..

Answer 10

In last term you have done : \(2(a-b)\)

Instead do : \(2 \cdot a \cdot b\)

Answer 11

that means:

a = 4x here and b = 3 here..

So

\[\implies (4x)^2 + (3)^3 - 2(4x)(3)\]

Answer 12

That is 3^2 there..

Answer 13

\[\implies (4x)^2 + (3)^2 - 2(4x)(3)\]

Answer 14

Getting RH??

Answer 15

Yes yes I am sorry my connection is not working well. I understand it now. How do I distribute 2(4x)(3)

Answer 16

(8x)(3) ?

Answer 17

multiply the binomial (4x-3) * (4x-3)

Answer 18

your answer is B

Answer 19

\[16x ^{2} + 9 - (4x-3) (4x-3)\]

Answer 20

like this? is this correct? @aliera95

Answer 21

no.. its 16x^2-24x+9

Answer 22

can you tell me how you got that answer??? I can't seem to get it:(

Answer 23

since the binomial is being squared you multiply \[(4x-3) \times (4x-3) \] you then refer to the foil method. multiply the first term of the first binomial that is 4x and multiply it by the 1st and 2nd terms of the 2nd binomial.

Answer 24

do the same method for the 2nd term of the 1st binomial. multiply -3 to the 1st and 2nd terms of the 2nd binomial

Answer 25

finally do common like terms

Answer 26

I got B as the answer