Question

Stats help:
A card is drawn from a well shuffled pack of cards.Then a second card is drawn.Find the probability that both are spades if first card is not replaced before the second is drawn.

Answer 1

are there jokers?

Answer 2

That's the question.After that it says nothing.

Answer 3

lets take there is no joker..
let A is the probability of first card being a spade...
P(A)=13C1/52C1
agree?

Answer 4

Okay so there are like 52 cards in one set and from them 13 are spade?

Answer 5

yes...!

Answer 6

both are spade it says..?

Answer 7

let B be the probability of second card being a spade...
so P(B)=12C1/51C1 as there is no replacement
agree?

Answer 8

12? where is it coming from? spade is 13 no?

Answer 9

first card is not replaced ...so there is 12 other spades.

Answer 10

I don't get it -_-

Answer 11

ok, 13 spades in 52 cards
when 1st card is drawn,
P(spade) = # of spades / total # of cards = 13/52
clear till here ?

Answer 12

Yes :3

Answer 13

good!
now we have drawn out one of the spade out of 13 spades,
how many remain ?

Answer 14

12.

Answer 15

right, and in total number, 51 will remain.
so, P (2nd card to be spade) = # of remaining spades / # of remaining total cards = 12/51
clear ?

Answer 16

Yes clear.

Answer 17

now last part,
probability that both are spades = P (1st card is spade ) AND P (2nd card is spade)

since there's a AND , we will multiply these events (probability of events)

probability that both are spades = (13/52) times (12/51) = ... ?

Answer 18

0.058823

Answer 19

correct !

Answer 20

or you can keep it as 3/51

Answer 21

Oh that's all :3,thankyou guys :3

Answer 22

you are welcome...

Answer 23

welcome ^_^