Lucy has a bag of M&Ms. There are 15 blue, 7 brown, 10 green, 13 orange, 5 red, and 6 yellow candies in her bag. What is the probability that she will get a green M&M by drawing a random candy from the bag?

Question

anonymous · Answer

well the total m&m's are 56.

So all you do is
$$\frac{ 10 C 1 }{ 56C1 }$$

Which I think is 17.9 %

dan815 · Answer

there are 
10 green m and m
there are 56 in total
so every 10/56 will be green

dan815 · Answer

if she reaches into her bag, there is a 10/56 change she will pick up an m and m okay

dan815 · Answer

you can simplify that fraction down too

dan815 · Answer

chance*

anonymous · Answer

you can just do 10/56....

anonymous · Answer

thats what i thought but i wasnt sure if i was missing something, just seemed to easy.

dan815 · Answer

yeah dont get confused these questions are supposed to be easy, they just want you to start thinking

anonymous · Answer

i have a another question then, can you guys walk me through this type of question:

There are 20 players on a hockey team. 5 of them are rookies. Determine the probability that none of the rookies will be randomly selected to be included in the team's group of 6 starters.

cause i have no idea how to do these.

dan815 · Answer

okay so

dan815 · Answer

what do you think about it

dan815 · Answer

let me get you started, if none of the rookies will be selected, you team will have all seasonsed players
so 6 started who are all seasoned, what is the probability of that

anonymous · Answer

6/20 ?

dan815 · Answer

no xD

dan815 · Answer

look at this picture

dan815 · Answer

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