The circle with center A and radius AB is inscribed in the square here. AB is extended to C. What is the ratio of AB to AC?
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let me add a few things to your drawing:|dw:1373224388864:dw| since AB is radius of the circle, we will call it R now look at the triangle ACD. it has 3 sides: AC, AD, CD and the angle at point B is 90 degrees, hence we can apply the Pythagorean theorem \[c ^{2} = a ^{2} + b ^{2}\]\[AC ^{2} = AD ^{2} + CD ^{2}\] from the given picture we see that AB, AD and CD are all the same length, length of radius of given circle, hence all of them = R \[AC ^{2} = R ^{2} + R ^{2}\]\[AC ^{2} = 2*R ^{2}\] we square all of it and get: \[AC = \sqrt{2}*R\] and now, you are looking for AB/AC. can you tell me what is the answer?
OH NO!
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