Question

HELP!! PLEASE JUST TELL ME HOW TO SOLVE IT! Find the length of the minor axis for the ellipse defined by this equation: ((x+2)^2)/(1)+((y+9)^2)/(64)=1

Answer 1

((x+2)^2)/(1)+((y+9)^2)/(64)=1

((x-(-2))^2)/(1^2)+((y-(-9))^2)/(8^2)=1

it is now in the form (x-h)^2/a^2+(y-k)^2/b^2=1 where

h = -2
k = -9
a = 1
b = 8


the values of and a and b determine the lengths of the major and minor axis

the smaller value a = 1 is the length of the semi-minor axis (since the minor axis is shorter than the major axis)

so 2a = 2*1 = 2 is the length of the minor axis

Answer 2

Thank you!