Find the zeros for the following polynomial function and give the multiplicity for each zero state whether the graph crosses the x-axis or touches and turns around... f(x)=9(x+8)(x+6)^3 What is the value of the zero with the smaller multiplicity?
well, if you set the equation to 0 that is \(\bf 0=9(x+8)(x+6)^3\) the roots are really obvious \(\bf0= 9(x+8)(x+6)^3 \implies 0 =9(x+8)(x+6)(x+6)(x+6)\)
now you have really 2 non-repeated roots the one raised to 3, is really the root with the multiplicity of 3 so the multiplicity will be the exponent of the binomial for that root so the other will have the "smaller" multiplicity
does it cross or just touch the x-axis? well, keep in mind that, if the multiplicity, the exponent, is EVEN, it "touches" only, if it's ODD, it "crosses"
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