Question

Simplify


(8y^)-2

Answer 1

\[(8y)^{-2}\]

is that what it looks like?

Answer 2

yes

Answer 3

okay well when you have negative exponents, to make the exponents positive, you put them in a denominator over 1, so:

\[(8y)^{-2} = \frac{ 1 }{ (8y)^{2} }\]

Answer 4

now just square the bottom

Answer 5

so the answer would be 64y2?

Answer 6

\[\frac{ 1 }{ (8y)^{2} } = \frac{ 1 }{ 8^{2}y^{2} }=\frac{ 1 }{ 64y^{2} }\]

Answer 7

so write the answer as 1 over 64y2?

Answer 8

thanks

Answer 9

yes, it is a fraction