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Find the foci of the hyperbola defined by this equation: ((x-4)^2)-(1)-((y+4)^2)-(9)=1
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\[\frac{(x-4)^2}{1}-\frac{(y+4)^2}{9}=1\]
Is that the problem?
yes
\[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]
That is the equation of a hyperbola with center (h,k)
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ok
a^2+b^2=c^2
So identify a^2 and b^2 and use them to find c because the foci are c units to the right and c units to the left of the center.
I don't know how to do that....
What is a^2?
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1^2
The number in your equation that replaces a^2 is 1
What is b^2?
9
Now take the equation I posted. Replace a^2 with 1. Replace b^2 with 9. Solve for c
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10?
c^2=10 so c is sqrt10
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