integrate dx/(1-cosx)
dammit!!!! omg you read my mind lmao.
another way is to use double angle formula. cos 2x =... ?
@shamim several methods are being shown here, which way you would like to proceed ?
I dropped mine. Only gets more convoluted.
confused
do u know integration of cosec^2 x ?
no
i'll tell you before that can you tell me all formulas for cos 2x that you know ?
\[\large \int \cfrac{1}{1- \cos(x)}dx\]\[\large \int \cfrac{1}{1- \cos(x)} \cdot \cfrac{1+ \cos(x)}{1+ \cos(x)}\]\[\large \int \cfrac{1+ \cos(x)}{1- \cos^2 (x)}dx\]\[\large \int \cfrac{1+ \cos(x)}{ \sin^2 (x)}dx\]
go on @Jhannybean
i m getting ur solution
@Jhannybean
rewrite \( \sin^2(x)\) as \( \csc^2 (x)\) and integrate.
please show every steps
sorry
Try it out. Integrate \[\large \int (1+ \cos(x))( \csc^2 (x))dx\] You can do it :) Tell me what you get and i'll check with my methods of solving the problem
then
i m not able to do this integration
Yes,you can do it... distribute csc^2(x).What do you get?
bt i understood ur steps
show plz
I've got to head off the computer, @hartnn can help you finish :D
@shamim why don't you atleast give a shot, whats (cosec^2 x)(1+cos x) =... ? u know basic trigonometric identities, right ?
\[cosec ^{2}x+cosec ^{2}x cosx\]
From WolframAlpha:
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