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OpenStudy (anonymous):

Need your help. How can I determine an even and odd function?

OpenStudy (rsadhvika):

take the given function, put x = -x if f(x) = f(-x), then its even if (x) = -f(x), then its odd if you dont get one of the above, then its neither even or odd.

OpenStudy (anonymous):

can you give me some examples? @rsadhvika i really need to understand it

OpenStudy (rsadhvika):

f(x) = x^2

OpenStudy (rsadhvika):

test and see if its even or odd

OpenStudy (rsadhvika):

f(x) = x^2 put x = -x, f(-x) = (-x)^2 = x^2 = f(x) since, f(-x) = f(x), its an even function.

OpenStudy (anonymous):

even?

OpenStudy (rsadhvika):

yes, lets do another example :- f(x) = x^3

OpenStudy (anonymous):

odd ?

OpenStudy (rsadhvika):

yes, one more :- f(x) = x^2 + 1

OpenStudy (anonymous):

even

OpenStudy (rsadhvika):

actually no

OpenStudy (anonymous):

aw.. ;'(

OpenStudy (rsadhvika):

f(x) = x^2+1 put x = -x f(-x) = (-x)^2 + 1 = x^2 + 1 = f(x)

OpenStudy (rsadhvika):

you're right actually, im wrong, its even :)

OpenStudy (rsadhvika):

i want to give u one example, which is neither even or odd. let me think...

OpenStudy (anonymous):

okay ^^

OpenStudy (rsadhvika):

try this : f(x) = x^2+x

OpenStudy (anonymous):

okay this is hard. Is it an odd?

OpenStudy (rsadhvika):

f(x) = x^2+x put x=-x, f(-x) = (-x)^2-x = x^2-x

OpenStudy (rsadhvika):

its neither f(x) or -f(x) so its not even not odd.

OpenStudy (anonymous):

how can you determine if the function is not even and odd?

OpenStudy (rsadhvika):

f(x) = x^2+x put x=-x, f(-x) = (-x)^2-x = x^2-x after doing above, lay back and look at what u got

OpenStudy (rsadhvika):

u got x^2-x x^2-x \(\ne\) f(x) x^2-x \(\ne\) -f(x)

OpenStudy (rsadhvika):

so its, not even, not odd

OpenStudy (anonymous):

I see ! I get it now Thank you @rsadhvika

OpenStudy (rsadhvika):

:)

OpenStudy (anonymous):

@rsadhvika now , how can you determine if the function is increasing or decreasing?

OpenStudy (rsadhvika):

we need to look at graph

OpenStudy (rsadhvika):

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