Need your help. How can I determine an even and odd function?
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OpenStudy (rsadhvika):
take the given function,
put x = -x
if f(x) = f(-x), then its even
if (x) = -f(x), then its odd
if you dont get one of the above, then its neither even or odd.
OpenStudy (anonymous):
can you give me some examples? @rsadhvika i really need to understand it
OpenStudy (rsadhvika):
f(x) = x^2
OpenStudy (rsadhvika):
test and see if its even or odd
OpenStudy (rsadhvika):
f(x) = x^2
put x = -x,
f(-x) = (-x)^2
= x^2
= f(x)
since, f(-x) = f(x), its an even function.
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OpenStudy (anonymous):
even?
OpenStudy (rsadhvika):
yes, lets do another example :-
f(x) = x^3
OpenStudy (anonymous):
odd ?
OpenStudy (rsadhvika):
yes, one more :-
f(x) = x^2 + 1
OpenStudy (anonymous):
even
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OpenStudy (rsadhvika):
actually no
OpenStudy (anonymous):
aw.. ;'(
OpenStudy (rsadhvika):
f(x) = x^2+1
put x = -x
f(-x) = (-x)^2 + 1
= x^2 + 1
= f(x)
OpenStudy (rsadhvika):
you're right actually, im wrong, its even :)
OpenStudy (rsadhvika):
i want to give u one example, which is neither even or odd. let me think...
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OpenStudy (anonymous):
okay ^^
OpenStudy (rsadhvika):
try this :
f(x) = x^2+x
OpenStudy (anonymous):
okay this is hard. Is it an odd?
OpenStudy (rsadhvika):
f(x) = x^2+x
put x=-x,
f(-x) = (-x)^2-x
= x^2-x
OpenStudy (rsadhvika):
its neither f(x) or -f(x)
so its not even not odd.
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OpenStudy (anonymous):
how can you determine if the function is not even and odd?
OpenStudy (rsadhvika):
f(x) = x^2+x
put x=-x,
f(-x) = (-x)^2-x
= x^2-x
after doing above, lay back and look at what u got
OpenStudy (rsadhvika):
u got x^2-x
x^2-x \(\ne\) f(x)
x^2-x \(\ne\) -f(x)
OpenStudy (rsadhvika):
so its, not even, not odd
OpenStudy (anonymous):
I see ! I get it now
Thank you @rsadhvika
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OpenStudy (rsadhvika):
:)
OpenStudy (anonymous):
@rsadhvika now , how can you determine if the function is increasing or decreasing?