Question

A gamma ray with an energy of 3.40 × 10-14 joules strikes a photographic plate. We know that Planck's constant is 6.63 × 10-34 joule·seconds. What is the frequency of the photon?
Select one of the options below as your answer:

A.
5.13 × 1019 hertz
B.
5.60 × 1017 hertz
C.
2.45 × 1017 hertz
D.
2.45 × 10-12 hertz
E.
7.80 × 10-19 hertz

Answer 1

can someone plug this in for me and ill solve it im bad at doing that stuff

Answer 2

The relation is (which u must be knowing) \(E=h\nu\)
where \(E \) is energy which is given to be as 3.40×10\(^{-14}\) J.
\(h\) =6.63×10\(^{-34}\) Js.
Just put these values in the above and find \(\nu\),the frequency.

Answer 3

ok ty ill try it out now

Answer 4

what would be the v?

Answer 5

You have to find it. It is the frequency

Answer 6

ok

Answer 7

should I use a regular calcuklator or could it work on mathway.com?

Answer 8

use a scientific calculator

Answer 9

ok ill try it out

Answer 10

on the scientific calculator on the computer how do I do 10^-14?

Answer 11

-14 on top

Answer 12

do not calculate the powers of 10...you can make out without calculator

Answer 13

idk if i can tbh

Answer 14

I really didnt learn this...

Answer 15

3.40/6.63=?

Answer 16

its A?

Answer 17

what did u get?0.513?

Answer 18

yes

Answer 19

0.5128

Answer 20

well u just round

Answer 21

now 10^-14/10^-34=10^20
so the answer is A

Answer 22

ok cool ty