PLEASE HELP, For a rectangular prism, if the base length was shrunk by a factor of two-thirds, the width was quadrupled, and height was cut in half, how would the changes affect the surface area formula?

Question

anonymous · Answer

Heres the problem again with answers.

mathstudent55 · Answer

The total surface area of a rectangular prism is:
SA = 2LW + 2LH + 2WH
Now take the length, L, and replace it with 2L/3.
Take the width, W, and replace it with 4W.
Take the height, H, and replace it wirth H/2.
Make all thses substitutions in the formula above and figure out the result.

anonymous · Answer

SA=2L/3+2L2+24/2 LIKE THAT?

anonymous · Answer

Im not getting your instructions..

mathstudent55 · Answer

L is substituted by 2L/3.
The first term of the surface area is 2LW. 
L now becomes 2L/3, and W now becomes 4W, so 2LW becomes 2 * (2L/3) * (4W)

anonymous · Answer

im still confused..

anonymous · Answer

So my base is 1/16 ?

mathstudent55 · Answer

$SA = 2~~~~~L~~~~~~W ~~~~+2~~~~~L~~~~~~~~H~~+~2~~~W~~~~~~H$
$SA = 2(2L/3)(4W) + 2(2L/3)(H/2) + 2(4W)(H/2)$

anonymous · Answer

So is D my answer?

mathstudent55 · Answer

$SA = \frac{16}{3} LW + \frac{2}{3}LH + 4WH$

anonymous · Answer

C. Thanks.

mathstudent55 · Answer

That's it. Wlcm.