Question

\[\int\limits \frac{ secxtanx }{ 4+\sec^2x }\]

Answer 1

im pretty much lost with the trig functions

Answer 2

i know i have to use inverse functions but secxtanx, is the inverse just secx?

Answer 3

a simple substitution of secx = t will help your case.

Answer 4

could you show me?

Answer 5

secx = t
secx tanx dx = dt

rest is easier

Answer 6

so is it u/4+sec^2x ?

Answer 7

nop o.O
it becomes

dt/(4 + t^2)

Answer 8

\[\frac{ secxtanx }{ 4 + (secxtanx)^2 }= 1/4 +\sec x tanx\]

Answer 9

is that my answer or am i still way off?