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OpenStudy (anonymous):
What is the magnitude and direction of Vector GH if G(2, -2) and H(7, 6)?
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OpenStudy (anonymous):
magnitude: 9.43 units; direction 32.01
magnitude: 6.4 units; direction: 57.99°
magnitude: 9.43 units: direction: 57.99
magnitude: 6.4 units: direction: 32.01
OpenStudy (jdoe0001):
is that G+H? or \(\bf G \cdot H\)?
OpenStudy (anonymous):
its a vector
OpenStudy (anonymous):
so plus i think
OpenStudy (jdoe0001):
well, the G+H will be = <2+7, -2+6> => <9, 4>
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OpenStudy (jdoe0001):
\(\bf \text{magnitude of a vector} \\ ||v|| = <a, b> = \sqrt{a^2+b^2}\)
OpenStudy (jdoe0001):
and the angle or direction is going towards comes from the angle from
\(\bf \cfrac{v}{||v||}\)
OpenStudy (jdoe0001):
well, that wont' give you much of an angle, but if you take the tangent of the 2 components, should
OpenStudy (anonymous):
ok thanks
OpenStudy (jdoe0001):
thus the GH = <9, 4> is moving at the angle of
$$
tan(\theta)= \frac{4}{9}\\
\theta = tan^{-1}\pmatrix{\frac{4}{9}} \implies 23.96^o
$$
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OpenStudy (anonymous):
right...
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