Ill give a medal (: What is the solution of the equation 3^x =12?
take log in both sides
I dontnw how to do thatok
Sorry my keyboard is messing up
do u know logarithms ?
!no
there is property of logarithms that...\[\log_{10}a ^{b}=b \log_{10}a \] if you take log in your equation... \[\log_{10}3^{x}=\log_{10}12 \] now use that property..
Wait i dont understand what i would do after that
The answer is x=\[\frac{ \log_{12} }{\log_{3} ? }\]
$$\large { 3^x =12\\ log_3(3^x) = log_3(12)\\ \text{using the log cancellation rule of}\\ \color{blue}{log_aa^x = x}\\ x = log_3(12) } $$
Ohh a o(: uy knah tdnatsrednuiykohh
and you can use the "change of base rule" to get the actual value using \(log_{10}\) only $$ large { log_3(12)\\ \text{using log change of base rule}\\ log_3(12) \implies \cfrac{log_{10}12}{log_{10}3} } $$
woops, darnheh
$$ \large { log_3(12)\\ \text{using log change of base rule}\\ log_3(12) \implies \cfrac{log_{10}12}{log_{10}3} } $$
Oops im sorrym oard is messing up on my ipad
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