Which value is the solution for the equation cotx/2=-1? A. 3pi/2 B. 3pi/4 C. 5pi/4 D. 7pi/4
cot(x/2) or cot(x)/2?
The first one
First solve \[x/2=cot^{-1}(-1)\]. Then you have a normal equation for which you can solve x. Don't forget that there are multiple possible answers for arccot. It's of the form (...+k*pi with k element of Z)
$$ \bf \large { cot\pmatrix{\frac{x}{2}} = -1\\ cot^{-1}\pmatrix{cot\pmatrix{\frac{x}{2}}} = cot^{-1}(-1)\\ \frac{x}{2} = \frac{3 \pi}{4}, \frac{7 \pi}{4}\\ } $$
or you can plug in choices one by one and see which one satisfies your equation...
Nvm totally wrong :p
I can only pick one....
lets try 1st one, cot (x/2) = cot (3pi/4) = ... ?
$$ \frac{x}{2} = \frac{3 \pi}{4}, \frac{7 \pi}{4}\\ \frac{x}{2} = \frac{3 \pi}{4} \implies x = \frac{3 \pi}{2}\\ \frac{x}{2}=\frac{7 \pi}{4} \implies x = \frac{14 \pi}{4} $$
I think its A
correct :) because cot (3pi/4) = -1 ...
yes, the other choice will be \(\cfrac{7\pi}{2}\) and is not in the choices
A is correct!
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