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How do you use the formula V = l^3 for the volume of a cube of side l to find (a) the average rate at which the volume of a cube changes with l as l increases from l = 2 to l = 4 (b) the instantaneous rate at which the volume of a cube changes with l when l = 5.
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define V at I=4 and I =2, then divide the difference by 4-2
then define the derivative at I=5
why they want to define a side by I instead of s is beyond me: a)\[\frac{4^3-2^3}{4-2}\] b)\[V=s^3\]\[V'=3s^2\]
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