Question

Find the domain of the following function

Answer 1

[1-e^(x^2)]/1-e^(1-x^2)

Answer 2

having difficulty expressing it in the equation applet

Answer 3

Domain...what value(s) of 'x' would make the denominator in this equation = 0?

\[1 - e^{1 - x^2}\]

Do any values for 'x' make that = 0...?

Answer 4

I have a better representation of the expression

Answer 5

Right....as I have posted above

\[\large 1 - e^{1 - x^2}\]

*the question is asking you to see if the domain is all real numbers...or if there are some values that would make this equation not work..

Remember that you cannot divide by 0...so you are only focusing on the denominator part of this equation. (posted above)

So you need to find....what values of 'x' would make this = 0

Answer 6

x=1 is the only number that comes to mind

Answer 7

that is 1 solution...but remember that 'x' is squared...(negative would become positive)....so another answer would be...?

Answer 8

x= +/-1 then

Answer 9

Right!

So we found that +/- 1 are not included in this domain

So what would your domain be?

Answer 10

or rather, all real numbers not equal to 1 or -1

Answer 11

That would be correct

Answer 12

awesome, thank you for helping simplify it for me

Answer 13

No problem!