Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = 2/3x − 10

y = 2/3x + 10

y = −3/2x − 10

y = −3/2x + 10

Answer 1

If its perpendicular, then the slope is is the negative reciprocal of the original slope

Answer 2

so if the slope was 5x then the perpendicualr slope is -1/5x

Answer 3

so the answer is A?

Answer 4

nope first you gotta get it into y=mx+b form

Answer 5

can you solve for y?

Answer 6

yes Y=mx+b

Answer 7

i mean B is the answer

Answer 8

i meant in the above equation its not in the form Ax+By=C

Answer 9

B is totes the answer right?

Answer 10

not quite you gotta do a little work first here: 2x − 3y = 3

Answer 11

how about C

Answer 12

-3y=-2x+3
y=2/3x-1

Answer 13

now m=slope has to be the opposite reciprocal, do that

Answer 14

and then pllug the slop in, with the point, in the point slope formula which is
y-y1=m(x-x1) where
y1=2 and x1=-8 and when you solve for y, you get your answer

Answer 15

ca you solve for y for me idk how 2 do it

Answer 16

I'm here to help not answer but what is the negative reciprocal of 2/3?

Answer 17

whats reciprocal

Answer 18

the reciprocal of \[\frac{ a }{ b }
is
=\frac{b}{a}\]

Answer 19

so the answer is -3/2

Answer 20

yes now with m=-3/2 y1 being the y coordinat of (-8,2) and x1 being the x coordiante of it, plug the slope and the point into the point slope formula and tell me what you get (the other x and y dont change)

\[y-y1=m(x-x1)\]

Answer 21

the answer is C

Answer 22

you got it

Answer 23

woo!