Question

What is the product of the radical expression?

Answer 1

\[(\sqrt{2+\sqrt{10)}}(\sqrt{2-\sqrt{10)}}\]

Answer 2

@satellite73 ? would u know this 1

Answer 3

@danber8

Answer 4

is it
\[(\sqrt{2}+\sqrt{10})(\sqrt{2}-\sqrt{10})\]?

Answer 5

if so, then it is ok since \((a+b)(a-b)=a^2-b^2\) giving you \(2-10=-8\)

Answer 6

gotcha i just had to double look the problem ty!

Answer 7

\[\left(\sqrt{2+\sqrt{10}}\sqrt{2-\sqrt{10}}\right)^2=-\left(-2+\sqrt{10}\right) \left(2+\sqrt{10}\right) \]\[-\left(-2+\sqrt{10}\right) \left(2+\sqrt{10}\right)=-6 \]\[\sqrt{-6}=i \sqrt{6} \]

Answer 8

sry @robtobey that wasnt a choice - 8 is correct

Answer 9

@britbrat4290

Recheck your problem statement.\[\left(\sqrt{2+\sqrt{10}}\right)\neq \left(\sqrt{2}+\sqrt{10}\right) \]