85.0 grams of potassium bromide are to be used to produce a 0.300 M solution. What will be the total volume of this solution?

Question

anonymous · Answer

85.0 g/molar mass KBr = moles KBr. 
M = moles/L of soln. 
85.0g/119.0023molesKbr=.7142719
.7142719/.300M=2.3809

anonymous · Answer

i think that's correct.

rane · Answer

u answered the q' yourself

theeric · Answer

Yep! I believe that's correct - my only discrepancy is the units!

85.0 g/molar mass KBr = moles KBr. 
M = moles/L of soln. 
85.0g/119.0023molesKbr=.7142719$\qquad\leftarrow$ Instead of molesKBr, it should be g/molesKBr
.7142719/.300M=2.3809

And the units of .7142719 are in molesKBr.