Question

Solve for the distance between the given point and the intersection of the system.
1. -2x+5y=1
1/2x-1/3y = 1
A (0,1)
Help me? :)

Answer 1

... u need some brackets in your question there...
is it:

\[(1/2x) - (1/3y) = 1\]
or
\[[1/(2x-1)] /3y = 1\]

Answer 2

its the first one, yeah?
0.5x - 0.333y = 1?

Answer 3

@AnyaBerrie ?

Answer 4

(1/2x)−(1/3y)=1
Sorry, for the late reply. :)

Answer 5

all good,
so where did u calculate that those 2 lines intersect?

Answer 6

That's the question given by my teacher. I don't really understand it. Maybe I need to solve the values of the two equations? :)

Answer 7

no, you should work out first where the 2 lines touch
they're both linear equations, so when u graph them they'll be straight lines
unless they have exactly the same slope, they will cross at some point, so you need to find that point

Answer 8

now you can do it by graphing the 2 lines, and seeing physically where they cross

or

you can work it out mathematically.
which would u prefer?

Answer 9

Wow. Thank you for helping me. Mathematically please. :)

Answer 10

sorry champ, i went to sleep yesterday

ok what you want to do is solve the simultaneous equation first to work out when the 2 lines intercept eachother:

so the equations
EQN 1: -2x + 5y = 1
EQN 2: (1/2)x - (1/3)y = 1

but subbing x = 2.5y - 1 (rearranged EQN 1) into EQN 2

you get that the lines intercept each other at
x = 32/11 , y = 15/11
that's approximately
x = 2.91, y = 1.36

Answer 11

so the given point is (0,1)
and the intercept point is (2.91, 1.36)
so you can use triangulation to work out the distance from I P to G P

Answer 12

so this makes a right angled triangle, so you can use pythagorus theorum to work out the hypotenuse (use below equation)

\[h^2 = a^2 + b^2\]
in this example a = 2.91
and b = 0.36

solve for h, and thats your final answer

sorry for the delay ;)