Question

Given tan theta=4/3 and sin theta=-4/5, find cos theta.


A.1/3
B.-1/3
C.3/5
D.-3/5
E. -SQRT 3/5

Answer 1

\[\tan \theta =\frac{ \sin \theta }{ \cos \theta }\]
so \[\cos \theta=\frac{ \sin \theta }{ \tan \theta}\]

Answer 2

-4/5
------
4/3?

Answer 3

right...

Answer 4

thank you!

Answer 5

you are welcome........

Answer 6

= -3/5 :D

Answer 7

correct!

Answer 8

can you help me with one more pls?

Answer 9

Which expression is equivalent to tan(-x)cos2x?


A.

-sin xcos x




B.
sin xcos x




C.
tan x + sin2x




D.
tan x − sin2x




E.
-tan x − sin2x

Answer 10

tan(-x)=-tanx
and cos2x=cos^2x-sin^2x

Answer 11

i dont understand this one

Answer 12

to my understanding then e is the only possible answer...

Answer 13

your question is tan(-x)*cos2x !
=-tanx[cos^2x-sin^2x]

Answer 14

but thats not an option