Question

please help. find the solution set and separate the two values with a comma:

X to the second-7x+6=0

Answer 1

so the equation is:
\[x ^{2} -7x +6 =0\]

are you familiar with the quadratic equation?

Answer 2

my teacher tried to show me that but it confused me so much

Answer 3

ok, to solve equation that have x^2 (x to the second) you use quadratic equation:

\[x _{1,2} = \frac{ -b \pm \sqrt{b ^{2}+4ac} }{ 2a }\]

your equation is in form of:
\[a*x ^{2} + b*x + c = 0\]

when you look this equation and your equation, could you tell me what are the values of a,b and c?

Answer 4

a is x^2 b is -7x c is 6?

Answer 5

you are very close, c is correct, just remove the x unknown.
coefficient can't have x in them:)

Answer 6

so B is -7 but what would A be?

Answer 7

when you have just x^2 it is the same as 1*x^2

Answer 8

C is 6, B is -7 and A is ...?

Answer 9

1

Answer 10

yes. now try plugging in the numbers in the quadratic equation in the third post:) tell me what you get

Answer 11

ok just one thing: what does x 1,2 mean on the equation

Answer 12

sorry, my bad, the equation goes sqrt(b^2 - 4ac)

Answer 13

x1,2 are the two solutions you will get when you solve the equation
x1 is the first solution
x2 is the second solution

you can see the plus/minus sign. that means your equation will spread into two; one with plus sign and one with minus sign; thus giving two solution

Answer 14

this equation
\[x _{1,2} = \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
will become
\[x _{1} = \frac{ -b + \sqrt{b ^{2}+4ac} }{ 2a }\]
\[x _{2} = \frac{ -b - \sqrt{b ^{2}+4ac} }{ 2a }\]