Question

i need help

Answer 1

You want to solve x? If so, you want to cross multiply.

Answer 2

We know that 3 * 1 =3
So what's (x-2) * (x) give us?

Answer 3

2x-2

Answer 4

Not quite. You want to do the distributive property.
So what's x(x-2)?

Answer 5

is it 1x-2

Answer 6

Well. What's
x *x give us?

Answer 7

1x

Answer 8

Nope. Here, I'll give you an example:
What's 2 * 2?

Answer 9

4

Answer 10

Good. What is another way of saying 2 * 2?

Answer 11

2+2

Answer 12

Nope.

Answer 13

Tip: exponent

Answer 14

2^2

Answer 15

Great! So what's
x *x give us?

Answer 16

x^2

Answer 17

Great. What's -2 * x?

Answer 18

-2x^2

Answer 19

Hmm. Tip: There's only one x. So what's it?

Answer 20

-2x

Answer 21

\[\frac{ x }{ x }\left( \frac{ x-2 }{ 3 } \right) = \frac{ 1 }{ x }\left( \frac{ 3 }{ 3 } \right)\]\[\frac{ x^2-2x }{ 3x } = \frac{ 3 }{ 3x }\]
\[\frac{ x^2-2x-3 }{ 3x } =0\]
divide both sides by the denominator , 3x

so you're left with \[x^2-2x-3\]
which can also be said as (x-3)(x+1)

sooo, we can find the values of x by....

x-3=0 or x+1=0

isolate for x on both equations.

x=3 or x= -1

there are two solutions to this equation, where the variable x could either be 3 or -1.

Answer 22

Hmm. I think I did something wrong.

Answer 23

Alexeis got it. Good job.

Answer 24

lol thanks. @GoldPhenoix
@Gustavo_xD do you understand what i did ?

Answer 25

yes thank you

Answer 26

Yes, I understand.