Question

A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?

Answer 1

the average acceleration \[a=\frac{ \Delta v }{ \Delta t}=\frac{ 43 }{ 0,28 }=153,6 \frac{ m }{ s^2 }\]

Answer 2

A.
12 meters/second2




B.
1.5 × 102 meters/second2




C.
78.6 meters/second2




D.
6.5 × 10-3 meters/second2

Answer 3

B if you round it off

Answer 4

thank you