A doctor performs 8 operations in a given day. Assume that the operations are independent, and each operation is a success with probability 0.95.What’s the probability that the doctor has exactly two failed operations on any given day? Calculate the exact binomial probability (do not use the normal approximation).
ff ssssss * how many permutations
binomial probability
(.95)^6 (.05)^2 (8 2)
:) (n k) is shorthand for a column vector
binomial probability formula is: http://www.allianthawk.org/images/stats%20binomial%20probability%20formula.gif so, you are looking for the probability that doctor has failed 2 operations, which is the same as the probability doctor has succeded 8 operations: k is the number of successful operations (8), n is the number of planned operations (10), p is probability of success now just plug that in the formula
is the binomial to close to zero or one? if so then we go poison
\[Poisson:~\frac{\mu^x~e^{-\mu}}{x!}\] \(\mu=np;~x=\#~desired\)
but they are asking for binomial, not poisson. or am I missing something?
im just adding some extra content is all :)
cool;)
Can anyone plz tell me the final answer with explanation?
we already have ...
well, the final answer is actually for you to calculate, the process has already been posted
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