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int \frac{ e ^{3x} }{(1+e ^{3x} )^{8}} dx
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let \[u =1+e^{3x}\rightarrow du =3e^{3x}dx\] and solve as usual
ok, thats where i got
is it 1/u^8 ?
\[\int\frac{e^3x}{(1+e^{3x})^8}dx\]is it yours?
yes
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ok, so i was thinking right....
yes, it turns \[\int \frac{1}{3}u^{-8}du\]
oh ok,...thats what i didnt see
so, you can step up from now, right?
yes, just substitute and that is final answer, right?
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u can go to denominator
take integral of this, it s\[\frac{1}{3}\frac {u^{-7}}{(-7)} + C\\=\frac{-1}{21u^7}+C\\=\frac{-1}{21(1+e^{3x})^7}\]
+ C at last
great. your awsome. thanks
yw
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