What information would you need to find the perimeter of to the right with vertices A(-3,1), B (-1,3) and C(3,1)?
you posted this already. I told you how to do it. why are you reposting?
because i dont understand and still need help im a slow learner especially in math and i need to work it out step by step and not so fast so i can at least understand a little
the ball was in your court to answer...
what
I gave you two subtraction problems. go back and look. http://openstudy.com/users/feedmefoooood#/updates/51dc15b9e4b0d9a104d9c4cb
i dont need to work the problem
i just need information to find the perimeter
to find the perimeter, you need to find the lengths of the sides. to find the lengths of the sides, you need to be able to use the distance formula. to use the distance formula to find the length of the first side, you need to do the subtractions I gave you.
and i did do them
ok you need to chill you are making me frustrated
good. now square both numbers and add them.
("good" responds to "did do them", not "making me frustrated", btw)
they are both 4
okay, add them
8
take the square root
i dont know how to do that without a calculator
can you factor 8?
i dont know what that means
factor means to find the numbers that multiply together to give you that number is 8 divisible by 2?
yes
okay, so 8 = 2*4, right? is 4 divisible by 2?
yes
okay, so 8 = 2*2*2, right?
yes
okay. square root means that for every pair of identical factors, we take one away and move the other one of the pair outside the square root sign. \[8 = \sqrt{2*2*2} = \sqrt{2*2}*\sqrt{2} = 2\sqrt{2}\] It is generally better to keep it in that form than to convert it to 2.828... while working the problem.
so, we have found the length of 1 of the 3 sides, that from A to B. Now we need to do B to C. Same drill: B is at (-1,3) C is at (3,1) \[(x_1,y_1) = (-1,3)\]\[(x_2,y_2) = (3,1)\] You need to plug those values into the formula \[d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] This formula is just taking the two sides of the triangles, squaring them, adding them, and taking the square root to find the hypotenuse. Pythagorean theorem.
what is \(x_2-x_1\)?
(3,-1)
no. look at the letters and numbers more carefully.
it's a subtraction, not a point.
4
right! now what is \(y_2 - y_1\)?
-2
yes. now look at your picture. look at the triangle formed from the line from B to C, plus a vertical line going down from B, and a horizontal line going from C. Do you see the triangle?
a line cutting it from B?
hang on a minute
triangle formed by the 2 dark red lines plus the line from B to C
ok yes that was what i was saying
okay, that's a right triangle, agreed?
yes
okay, the height of that triangle (the length of the side going from B down toward the x-axis) is how much?
4
look again, I'm talking about the line that goes from B to the spot 2 squares below it.
oh 3
try again. you're getting closer :-)
2??????
yes. and it is no coincidence that \(y_2 - y_1 = 2\)
now look at the bottom of the triangle. how many squares long is it? from the point we were just at (-1,1) over to C (3,1)
4
ill be back in about 20 minutes
very good. again, not a coincidence that \(x_2-x_1\) = 4. those are the two legs of our right triangle with the line from B to C as the hypotenuse. we square both of the lengths, add them, and take the square root to find the length of the line from B to C. \[d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{(3-(-1))^2+(1-3)^2} \]\[\sqrt{ 4^2+(-2)^2} = \sqrt{16+4}= \sqrt{20} \]\[= \sqrt{2*2*5} = \sqrt{2*2}*\sqrt{5} = 2\sqrt{5} \approx 4.472 \] Now, your job is to find the length of the side from C to A. This one is easier because they are on the same line and you can just count the squares, or subtract the x values — the y values are identical. the distance formula still works, of course, but isn't needed. when you know how long CA is, add that to your previous two sides, which were \[AB = 2\sqrt{2} \approx 2.828\] \[BC = 2\sqrt{5} \approx 4.472\] and you'll have your perimeter.
ok im backand its 12 right?
no. 12 is neither the length of CA nor the sum of the three sides. how did you get 12?
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