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PLEASE HELP ME What is the 35th term of the arithmetic sequence where a1 = 13 and a17 = -83? -200 -197 -194 -191
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you first need to find the common difference d then 35th term = a1 + ( 35 - 1)*d
you can find d by calculating (a17 - a1) / x what do you think x has to be?
i just need the answer, im taking a timed quiz
i dont know how to solve that
you can calculate a17 - a1 = -83 - 13
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and x = 17 - 1 = 16 terms
soo? after that
-83 = 13 + 16d ...and.. -96 = 16d d = -6 So... a_35 = 34(-6) + 13 = -204 + 13 = -191
HURRRY MY TEST IS ALMOST OVER
OKAY THANK YOU! :) SO MUCH.
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ALSO What is the sum of a 17-term arithmetic sequence where the first term is 6 and the last term is -90?
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