Question

solve
in an isosceles triangle ABC

Answer 1

If DE||BC
then
\[\angle ADE= \angle ABC ( corresponding - angles) -----1\]
Therefore \[x+y-36^0 =2x\]
\[y-36^0 =2x-x \]
\[y-36^0 =x ----(2)\]
Now since AB = AC (given)
therefore
\[\angle ABC= \angle ACB ( angles-opposite -equal-sides)\]Hence
2x=y-2
i.e. 2x-2 =y --------(3)
from 2 and 3 we have
2x-2-36^0 =x
2x-x =38^0
x=38^0

Answer 2

just plse check it again its x = 34 degree or 38 degree

Answer 3

It is x=38^0

Answer 4

y=2x-2 = 2*38-2=76-2=70^0