Question

A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 10^4 kilograms, what is the value of the impulse?
A)1.2 x10^4 kilogram meters/second
(B)2.2x10^5 kilogram meters/second
(C)7.1x10^5 kilogram meters/second
(D)3.6x10^4 kilogram meters/second

Answer 1

@souvik

Answer 2

@mr.singh

Answer 3

impulse=change in momentum...
so find change in momentum

Answer 4

c

Answer 5

impulse=m(v-u)

Answer 6

@souvik How do you do that and @mr.singh thank you it was right

Answer 7

that is.....mass*change in velocity

Answer 8

oww okay grazie :)