Question

What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = (-3/4)x-2?

Answer 1

so, what would you say is the slope of -> y = (-3/4)x-2?

Answer 2

answer choices are:
y=(4/3)x-12
y=(3/4)x-5
y=(-4/3)x+20
y=(-3/4)x+13

Answer 3

that slope would be down three, over four (-3/4), yes?

Answer 4

right, the slope for this -> y = (-3/4)x-2 <-- will be the -3/4

Answer 5

so, perpendicular lines have NEGATIVE RECIPROCAL slopes
what does that mean?

well, if this line's slope is -3/4
a perpendicular line to it will be
RECIPROCAL of -3/4
-4/3
NEGATIVE of that
4/3

Answer 6

so, now you know that the "other line" has a slope of 4/3, and it passes through (12, 4)
now use those 2 values in the point-slope form to get your line equation
\(\boldsymbol{\huge y-y_1=m(x-x_1)}\)
m = slope
use your (12, 4) = \(\bf (x_1, y_1)\)

Answer 7

dude... genius
so it would be y=(4/3)x-12, right?