Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4). y = four thirdsx + 8 y = four thirdsx + 3 y = −three fourthsx + 8 y = −three fourthsx + 3
what is the slope of the equation?
is it (-3,4)
okay y=?
y=4/3
no...
idk then what is it??
4x-3y=-12 or 3y=4x+12 of y=4/3x+4 so the slope is 4/3 get it?
wait is that the answer?
no ...
so what is the answer?
y-4=4/3(x+3) or y=4/3x+8
thanks!!
do u understand?
kinda i have another question?
ok
Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
find the slope first...
the slpoe is (6,-1) right??
no...
is it -3,7
3x+y=7 or y=-3x+7 so the slope is -3
oh so okay what do i do after that ??
Hi! Let me catch up, and then I'll be able to help!
Hi! First I'll lay out how to solve this problem. You've already made progress. You want to find a line perpendicular to the original line. By definition, you want a line that has a slope that's a reciprocal of the original line's.
So you found the original line's slope with souvik's help. Do you know what the slope is?
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