Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).
y = four thirdsx + 8
y = four thirdsx + 3
y = −three fourthsx + 8
y = −three fourthsx + 3
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OpenStudy (souvik):
what is the slope of the equation?
OpenStudy (anonymous):
is it (-3,4)
OpenStudy (souvik):
okay y=?
OpenStudy (anonymous):
y=4/3
OpenStudy (souvik):
no...
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OpenStudy (anonymous):
idk then what is it??
OpenStudy (souvik):
4x-3y=-12
or 3y=4x+12
of y=4/3x+4
so the slope is 4/3
get it?
OpenStudy (anonymous):
wait is that the answer?
OpenStudy (souvik):
no ...
OpenStudy (anonymous):
so what is the answer?
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OpenStudy (souvik):
y-4=4/3(x+3)
or y=4/3x+8
OpenStudy (anonymous):
thanks!!
OpenStudy (souvik):
do u understand?
OpenStudy (anonymous):
kinda i have another question?
OpenStudy (souvik):
ok
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OpenStudy (anonymous):
Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
OpenStudy (souvik):
find the slope first...
OpenStudy (anonymous):
the slpoe is (6,-1) right??
OpenStudy (souvik):
no...
OpenStudy (anonymous):
is it -3,7
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OpenStudy (souvik):
3x+y=7
or y=-3x+7
so the slope is -3
OpenStudy (anonymous):
oh so okay what do i do after that ??
OpenStudy (theeric):
Hi! Let me catch up, and then I'll be able to help!
OpenStudy (theeric):
Hi!
First I'll lay out how to solve this problem. You've already made progress.
You want to find a line perpendicular to the original line. By definition, you want a line that has a slope that's a reciprocal of the original line's.
OpenStudy (theeric):
So you found the original line's slope with souvik's help.
Do you know what the slope is?