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OpenStudy (anonymous):
Given sinx=-4/5 and x is in quadrant 3, What is the value of tan x/2?
I have an answer but I'm not sure it's right...
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OpenStudy (anonymous):
@hartnn Do you know?
hartnn (hartnn):
first find cos x from,
\(\sin^2 x +\cos^2x = 1\)
sin x = -4/5 is given...
OpenStudy (anonymous):
I think the answer is -2 because it's in the 3rd quadrant...
hartnn (hartnn):
in 3rd quadrant, tan ratio is positive!
OpenStudy (anonymous):
Oh yea sorry! I meant 2.
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hartnn (hartnn):
how u got 2 ?
hartnn (hartnn):
clarification required,
is it tan (x/2) or (tan x) /2 ??
OpenStudy (anonymous):
\[\tan(\frac{ x }{ 2 })= \sqrt{\frac{ 1-cosx }{ 1+cosx }}\]
OpenStudy (anonymous):
\[\pm \sqrt{\frac{ 1-(\frac{ -3 }{ 5 }) }{ 1+\frac{ -3 }{ 5 } }}\]
hartnn (hartnn):
yes, correct!
from that you will select +2 because tan is +ve in 3rd quadrant...
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OpenStudy (anonymous):
Thank you!
hartnn (hartnn):
ok, i got that you solved correctly :)
welcome ^_^
OpenStudy (anonymous):
It was wrong! It's -2!
hartnn (hartnn):
:O
we missed a point!
hartnn (hartnn):
x is in quadrant 3,
so, (x/2) will be in quadrant 2 !!
and tan is negative in quadrant 2....
silly mistake :(
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hartnn (hartnn):
sorry!
OpenStudy (anonymous):
It's ok... :(
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