Given sinx=-4/5 and x is in quadrant 3, What is the value of tan x/2? I have an answer but I'm not sure it's right...
@hartnn Do you know?
first find cos x from, \(\sin^2 x +\cos^2x = 1\) sin x = -4/5 is given...
I think the answer is -2 because it's in the 3rd quadrant...
in 3rd quadrant, tan ratio is positive!
Oh yea sorry! I meant 2.
how u got 2 ?
clarification required, is it tan (x/2) or (tan x) /2 ??
\[\tan(\frac{ x }{ 2 })= \sqrt{\frac{ 1-cosx }{ 1+cosx }}\]
\[\pm \sqrt{\frac{ 1-(\frac{ -3 }{ 5 }) }{ 1+\frac{ -3 }{ 5 } }}\]
yes, correct! from that you will select +2 because tan is +ve in 3rd quadrant...
Thank you!
ok, i got that you solved correctly :) welcome ^_^
It was wrong! It's -2!
:O we missed a point!
x is in quadrant 3, so, (x/2) will be in quadrant 2 !! and tan is negative in quadrant 2.... silly mistake :(
sorry!
It's ok... :(
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