Question

Using complete sentences, explain how to completely factor 2x2 − 6x − 36

Answer 1

Take the common?
2(x2 -3x-18)

Answer 2

2?

Answer 3

take the common ?

Answer 4

2 is the common.

Answer 5

no pellet but i need to know how to write out the answer

Answer 6

Be nice, or we wont help you.

Answer 7

Lol now you have to find the integral whose product is -18 and sum -3

Answer 8

if only you were helping then you could give input

Answer 9

I can solve this problem in my sleep. I am just trying to show proper etiquette by allowing @uri to fully help. You know, too many cooks in the kitchen.
But keep it up. It makes people want to help if you are rude and arrogant.

Answer 10

2 thumbs up for you big baller

Answer 11

I'm out.

Answer 12

Congrats @Chief1017 good job

Answer 13

appreciate it

Answer 14

First, find the common factor in all three terms. In this case, the answer is 2. So, when we divide by 2, we get: 2(x2 -3x -18)
Now there are no more factors common to all three terms.

We can factorize x2 -3x - 18 further. To do that, we have to find two numbers whose sum is -3 and product is -18. 3 and -6 meet these conditions.

Now we can write the polynomial as 2(x2 - 6x + 3x -18)

The first two terms inside the bracket have a common factor. So do the last two terms. Taking them out, we get 2(x(x-6) + 3(x-6))

Now we see that the factor x-6 is common between the two terms inside the bracket.
Taking that term out, we get
2((x-6)(x+3)) = 2(x-6)(x+3).

Further factorization is not possible.

I hope this is explanation enough.