Question

find the odds of an event if the probability of the event is given to be 1/13

Answer 1

The odds in favor of an event or a proposition is defined by the ratio of the probability that the event will happen to the probability that it will not happen.

mathematically, if p is the probability, odds = \(\dfrac{p}{1-p}\)

Answer 2

here p=1/13, just plug it in!

Answer 3

So the odds would be \[\frac{ 1 }{ 2 }\]

Answer 4

you mean 1/12 ?

Answer 5

if you meant 1/12 then you are correct.

Answer 6

I guess because that is one of the answers, but I got 1/2

Answer 7

I'm not getting 1/12

Answer 8

my options are 1:12, 1/13, 12/13, and 12:1

Answer 9

ok, \(\huge \dfrac{\dfrac{1}{13}}{1-\dfrac{1}{13}}=\dfrac{1}{13-13\dfrac{1}{13}}=...?\)

Answer 10

\(\huge \dfrac{\dfrac{1}{13}}{1-\dfrac{1}{13}}=\dfrac{1}{13-13\dfrac{1}{13}}=\dfrac{1}{13-1}\)
so, 1/12 = 1:12
got it ?

Answer 11

I think so. Thank you. :)

Answer 12

welcome ^_^