Question

Assuming all volume measurements are made at the same temperature and pressure, how many liters of carbon dioxide gas can be produced when 12.8 liters of oxygen gas react with excess carbon monoxide? Show all of the work used to solve this problem.

Balanced equation: 2 CO(g) + O2 (g) 2 CO2 (g)

Answer 1

any idea about how to solve this?

Answer 2

I think you use stoichimoetry but imnot sure how to do it

Answer 3

stoichiometry*

Answer 4

First look at the ratio
how many mol carbon monoxide is used to produce how many moles of carbon dioxide?

Answer 5

i think 2

Answer 6

yea 2 mol CO is used to produce 2 mol CO2
So the ratio is 2:2

But we are intersted in the mole ratio of O2 and CO2 (since we have a given volume of O2)
Do you know what this ratio is?

Answer 7

1 and 2?

Answer 8

i think that's right

Answer 9

yes 1 mol O2 is used to produce 2 mol CO2
So the ratio is 1:2

we know that 1 mol = 22.4 liter, that's a fact
So 1 mol O2 (22.4 L) gives 2 mol CO2 (22.4*2=44.8 L)

Now we have 12.8 liter O2, how many liter CO2 does that give you?

Answer 10

3.5?

Answer 11

How did you get that?

Answer 12

:/ I just divided 44.8 by 12.8

Answer 13

or was that completely wrong lol

Answer 14

i was gonna say 1/4

Answer 15

haha that is kinda wrong yea :)
Normally you would convert the volumes to moles, but since 1 mol = 22.4 liter, that's not necessary for this question.

the ratio is 1:2
so if you have 1, you multiply it by 2 to get 2 :)
now for 1 we have 12.8 liter
to get 2 we multiply that with 2
what do we get then?

Answer 16

25.6

Answer 17

siiiigh*

Answer 18

you wanted me to multiply 12.8 by 2 right?

Answer 19

Sorry i was away :P
And yes, that is correct
for 12.8 liter O2, 25.6 liter CO2 is produced

Answer 20

it's fine(:

Answer 21

that's the answer?

Answer 22

yes :)

Answer 23

thank you . you dont mind doing one last one por favor

Answer 24

I'm not doing it, but i'll help you with it :)

Answer 25

lol i know. ok cool (:

Answer 26

A solution is made by dissolving 10.2 grams of glucose (C6H12O6) in .315 kilograms of water. If the molal freezing point constant for water (Kf) is -1.86 °C/m, what is the resulting Δtf of the solution? Show all of the steps taken to solve this problem.