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Find the component form of the velocity of the airplane? An airplane is flying on a bearing of 335 degrees at 530 mph. Find the component form of the velocity of the airplane.
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I got <480.34, -223.99> but my book has it switced around
335 degrees translates to 25 degrees below the X axis. So we know the vector is positive in the X direction, negative in the Y direction. X component = 530cos(25) = 480mph Y component = -sin(25) = -223.99mph So i got (X,Y) = (480.34, -223.99) (although technically you should be rounding to 3 digits)
Lol I went to that site too with that answer
what site
yahoo
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oh sweetie i dont go on '"yahoo"
Funny cause thats the same exact reply the person made (your answer), idrc if you copy and paste
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