Question

Multiply and simplify: q^7*q*q^-9*q^-3
I attached a better way to describe the problem**

Answer 1

Really when you have the same base (q in this instnace) and they have differnet exponenet you just add them like
q^3 times q^2= (q^(2+3))=q^5

Answer 2

and if there isn;t an exponenet then its not a zero its a 1

Answer 3

so just add them together (the exponenets and tell me what you get)

Answer 4

I got q^-4 @doulikepiecauseidont but that's not a choice

Answer 5

ok well you can;t have it as that when you ave an exponenet to a negative power this what you do \[x ^{-2}=\frac{1}{x^{2}}\]

Answer 6

Thanks @doulikepiecauseidont

Answer 7

you just put it the denominator and make the exponent postive, its not the reciprocal because if you have something like this later on \[{y^{2}x^{-2}}=\frac{y^{2}}{x^{2}}\]