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Physics 18 Online
OpenStudy (anonymous):

If the period of a pendulum is 2.0 seconds and the acceleration due to gravity is 9.8 meters/second^2, What is the length of the cord on the pendulum? A)1.0 meters B)0.67 meters C)1.3 meters D)3.5 meters

OpenStudy (anonymous):

can you help me

OpenStudy (theeric):

Are you speaking of a simple pendulum?

OpenStudy (anonymous):

YES

OpenStudy (theeric):

Then you'll want the equation that uses math to describe the relationships between different physical quantities. I think I've show it to you before. I found it at http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html It is:\[T=2\pi\sqrt{\frac{L}{g}}\] \(T\) is the period. \(L\) is the length of the chord. \(g\) is the acceleration caused by gravity. You want to solve for \(L\).

OpenStudy (anonymous):

OKAY HOLD ON

OpenStudy (anonymous):

I GOT O.67 IS THAT RIGHT

OpenStudy (theeric):

It's not what I got! How did you solve for \(L\)?

OpenStudy (anonymous):

I squared 2 then i divided 2.0 by 9.8

OpenStudy (theeric):

I'm confused... Can you show me what you got? You squared the 2?

OpenStudy (anonymous):

now im confused cause your confused

OpenStudy (theeric):

Haha, you start with \[T=2\pi\sqrt{\frac{L}{g}}\]Now, what did you square?

OpenStudy (anonymous):

owwww okay i see what i did wrong i was suppost to pi the 2 instead of square

OpenStudy (theeric):

Hmmm?

OpenStudy (theeric):

I would divide the equation by \(2\pi\), square the equation, and multiply the equation by \(g\), if you know what I mean. Then you have \(L\) by itself after applicable cancelations, if you know what I mean.

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