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OpenStudy (anonymous):
Solve for x in the proportion:
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OpenStudy (anonymous):
\[\frac{ 2x }{ 16x + 30 }\]
= \[\frac{ -1 }{ x }\]
OpenStudy (johnweldon1993):
What do you get when you do this one?
OpenStudy (anonymous):
2x^2 = -16x - 30 <--- This is all I know to do.
OpenStudy (johnweldon1993):
That is correct.....do me a favor and add 16x and 30 to both sides...
You'll then have
\[\large 2x^2 + 16x + 30 = 0\]
Look familiar?
OpenStudy (anonymous):
So certain problems have to go to = 0? and some don't?
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OpenStudy (johnweldon1993):
Well no...but in the form I put it in...it is a quadratic equation....can be solved by factoring...makes it easier than guess and check
OpenStudy (anonymous):
Ahh okay. Let me find the factors of that.
OpenStudy (anonymous):
2(x + 3)(x + 5)
OpenStudy (anonymous):
Then to cancel out to 0, x + 3 would be -3 and x + 5 would be -5?
Which is the x's? -3 and -5
OpenStudy (johnweldon1993):
That would be correct! You can even check those answers by plugging then into the original equation
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OpenStudy (anonymous):
Alright, thank you. A quick question on a different question: 30x = 18x + 36 you would -18x get 12x = 36 then x = 3 right?
OpenStudy (johnweldon1993):
Correct again!
OpenStudy (anonymous):
Alrighty, thank you sooo much (:
OpenStudy (johnweldon1993):
No problem!
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