Completely lost on square rooting a quadratic x^2-8x+16=144. Don't I take 1/2 of the coefficient x^2-8x+4^2=144+2?
Do you want to find the roots?
Asked to solve using the square root formula.
The answer is -8 and 16, but I don't understand how to get there.
Factor that left hand side...what is a perfect square that comes out to x² - 8x + 16 ? (x .....)² ?
-4?
That might be a weird wording of it...here I'll help... oh nvm you got it...so you have (x - 4)² = 144 What would you do next using square roots?
subtract 16 from 144 which gives x^2-8x (x-4)^2=128
Nope....the 16 was in there when you factored the left hand side...remember (x - 4)² (x - 4) (x - 4) x² - 4x - 4x + 16 x² - 8x + 16 It was in there...no all we have now is (x - 4)² = 144 What you do next...is take the square root of both sides...
lost me with the 16...
I thought the x-4 was from dividing the coefficient 8x by 1/2.
Okay here.....what we wanted to do...was make it so we can use the square root property to solve this... meaning we had to make your equation x² - 8x + 16 = 144 look something like (x - or + something)² = 144 Because what we do next is take the square root of both sides... But we needed to find what that (x - or + something)² was You're factoring that left hand side .....the x² - 8x + 16 and when you factor that...you get (x - 4)²
No....what you are describing ...is called "completing the square"...it is another way to solve quadratics.. No what your question wants...is to use square roots
Really hope I'm not confusing the crap out of you lol
Oh no, I was already there :) just really getting confused. I think I'm intersecting one way doing things with another.
Yeah....you're trying to use "completing the square" method when trying to understand the "square root" method lol it would confuse anyone lol
I factor and get (x-1) (x+8)...what the heck am I doing here?
Lol okay lets try it 1 more time....you want to factor x² - 8x + 16 So what 2 numbers multiply to get 16 AND add to get -8?
-4
Right...so what this would look like is x² - 8x + 16 factors into (x - 4) (x - 4) Now it's dumb to write both of those when they're the same thing....so we write (x - 4)² make sense so far?
yes...think I'm tracking on a short lead..
Okay...now just don't forget that right hand part of the equation...the 144 part So we have x² - 8x + 16 = 144 This is now turned into (x - 4)² = 144 Okay? Because the x² - 8x + 16 has been factored...so it is replaced with the factor
x-4=12?
then solve for x?
GOOD! very close...but remember \[\sqrt{144} = \pm 12\] right? because -12² = 144 too right?
so you actually have 2 equations to solve x - 4 = 12 and x - 4 = -12 NOW solve for each 'x'
16 and -8...good grief!
Haha this is why there are 2 other methods of solving these....lol this method is annoying! haha.. But good job! Stuck with it till the end!
care to walk me through another?
Lol if I can yes! And I'll try to explain it better
6x^2=25
I was leading with division first but that didn't work so well.
The answer is +- 5\[+- 5\sqrt{6}\div6\]
Oh see NOW comes the easy one! lol Well it's not going to look pretty I'll tell you that \[6x^2 = 25\] Divide both sides by 6 \[x^2 = \frac{ 25 }{ 6 }\] Now take your square root of both sides \[x = \sqrt{\frac{ 25 }{ 6 }}\] Now this can also be written as \[x = \frac{ \sqrt{25} }{ \sqrt{6} }\] so the only thing that can be simplified is √25...this is +/- 5 right? so we have 2 answers \[x = \frac{ 5 }{ \sqrt{6} }\] and \[x = \frac{ -5 }{ \sqrt{6} }\]
And okay...the only difference between MY answers and yours...is that YOUR answer...has the denominator rationalized...
That is what I did..so that is it? The denominator is rationalized? Why the heck doesn't the book explain that simple little thing that has been driving me crazy for the past hour!!??
This is done by multiplying both the top and the bottom of the fraction by √6...this cancels out the √6 on the bottom...so \[x = \frac{ 5 }{ √6 } \times \frac{ \sqrt{6} }{ \sqrt{6} } = \frac{ 5\sqrt{6} }{ 6 }\] and \[x = -\frac{ 5 }{ √6 } \times \frac{ \sqrt{6} }{ \sqrt{6} } = -\frac{ 5\sqrt{6} }{ 6 }\] Lol yeah that's it lol
And lol yeah books are good at that lol...well if that is what you did...Great job!
Geez...thank you for clearing that up for me.
No problem! Great job and even better job sticking with it and not giving up when you didn't understand it!
I have no choice. This is my last class before graduating. LAST CLASS!!!
Very thankful I found this site.
WOO! lol well keep going strong! And yeah I found this site 2 months ago....It'll come in handy when I start calc 3 ...but for now...I'm just helping others lol
And I greatly appreciate that! Can you tell me what the medals are for that people offer up?
Medals is basically a reward "given by hitting the "Best Response" button to the side there" basically if you feel someone has helped you ...you give them a medal....And notice the little (24) near your name and the (81) near mine? That is called a smartscore....it goes up the more people you help...the more medals you get...the more questions you ask etc...
oh ok, got it! There you go!
Ahh, well thank you for that....as a matter of fact there YOU go *notice how your score just went from 24 to 26 now...
Yep! Thanks!
Well, gonna retire my brain for the evening. Need to unplug for a bit. Thank you for all your help!
No problem! Well you have a nice day / night depending on your time zone! lol
WA state :)
Ahh ...well have a nice night lol
You too
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