Question

The equation of a circle is (x - 8)2 + (y - 5)2 = 81. Where is (5, 1) located in relation to the circle?

answers:
On the circle
In the interior of the circle
In the exterior of the circle
At the center of the circle

Answer 1

its at the center of the circle yeah?

Answer 2

It can't be at the center of the circle because (8,5) is the center

Answer 3

so can it be on the circle?

Answer 4

does it satisfy the equation?

Answer 5

its in it too...

Answer 6

Input (x,y) = (5,1)

If equal to 81, then it is on the circle
If less than 81, then it is in the circle
If greater than 81, then it is outside of the circle.

Answer 7

its not greater then 81 i think

Answer 8

correct

Answer 9

so it is in the circle ?

Answer 10

correct

Answer 11

so the answer would be in the interior of the circle ?

Answer 12

or on the circle

Answer 13

you could also see that it is 3 spots to the left and 4 units up from the center
so that distance vector is <3,4> and |<3,4>| = 5 < 9

Answer 14

ohhh thats confusing

Answer 15

interior

Answer 16

all I said there is that the distance from your point is 5 away from the center, but your circle has radius 9, so it must be inside the circle

Answer 17

ohh okay i got it

Answer 18

thanks