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OpenStudy (anonymous):
rewrite the expression sin^2(2x) in terms of the first power of the cosine
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OpenStudy (anonymous):
\[1- \cos4x \div 2 \]
OpenStudy (anonymous):
Thanks! Can you provide an explanation to the solution?
OpenStudy (raden):
use the identity : sin^2 (p) = (1 - cos(2p))/2 now, change p = 2x, thus, sin^2 (2x) = (1 - cos(2 * 2x))/2 = (1 - cos(4x))/2
OpenStudy (anonymous):
Nice! Great explanation! Thanks so much! ;)
OpenStudy (raden):
you;re welc0me
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